## wtorek, 5 maja 2015

### Codility solutions - lesson1, exercise: PermMissingElem

Content of Codility excercise:

A zero-indexed array A consisting of N different integers is given.
The array contains integers in the range [1..(N + 1)], which means that exactly one element is missing.

Your goal is to find that missing element.

Write a function:

class Solution { public int solution(int[] A); }

that, given a zero-indexed array A, returns the value of the missing element.

For example, given array A such that:

A = 2
A = 3
A = 1
A = 5
the function should return 4, as it is the missing element.

Assume that:

N is an integer within the range [0..100,000];
the elements of A are all distinct;
each element of array A is an integer within the range [1..(N + 1)].
Complexity:

expected worst-case time complexity is O(N);
expected worst-case space complexity is O(1), beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.

Solution:

```    public int solution(int[] A) {
//Create tmp table with only elements equal 0,
int []tmpB = new int[A.length+1];
//Store in tmp table all element from table A.
for (int element: A){
tmpB[element-1] = element;
}
int missingElement = 1;
int i = 0;
// Now Tmp table contain one integer equal 0. Our solution will be index increased by 1 of such integer
while (missingElement != 0){
missingElement = tmpB[i];
i++;
}
return i;
}
```